Log[4](2x+3)-log[4](x+1)=1

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Solution for Log[4](2x+3)-log[4](x+1)=1 equation: 


Simplifying
Log[4](2x + 3) + -1log[4](x + 1) = 1

Reorder the terms:
goL * 4(3 + 2x) + -1log[4](x + 1) = 1

Reorder the terms for easier multiplication:
4goL(3 + 2x) + -1log[4](x + 1) = 1
(3 * 4goL + 2x * 4goL) + -1log[4](x + 1) = 1
(12goL + 8goxL) + -1log[4](x + 1) = 1

Reorder the terms:
12goL + 8goxL + -1glo * 4(1 + x) = 1

Reorder the terms for easier multiplication:
12goL + 8goxL + -1 * 4glo(1 + x) = 1

Multiply -1 * 4
12goL + 8goxL + -4glo(1 + x) = 1
12goL + 8goxL + (1 * -4glo + x * -4glo) = 1
12goL + 8goxL + (-4glo + -4glox) = 1

Reorder the terms:
-4glo + -4glox + 12goL + 8goxL = 1

Solving
-4glo + -4glox + 12goL + 8goxL = 1

Solving for variable 'g'.

Move all terms containing g to the left, all other terms to the right.

Reorder the terms:
-1 + -4glo + -4glox + 12goL + 8goxL = 1 + -1

Combine like terms: 1 + -1 = 0
-1 + -4glo + -4glox + 12goL + 8goxL = 0

The solution to this equation could not be determined.

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